Entri Populer

Selasa, 25 Januari 2011

Program to enter a character and output its ASCII code.


#include <iostream.h>
#include <conio.h>

void main()
{
clrscr();
char charac;
cout << "Enter the character : " << endl;
cin>>charac;
int num1=charac;
cout << "The ASCII code for " << charac << " is " << num1 << "." << endl;
getch();
}
This program takes in any character charac as a screen input from the user.
It then finds out its ASCII code and outputs it using the 'cout' command.

Program to enter a letter and output the next 2 letters


#include <iostream.h>
#include <conio.h>

void main()
{
clrscr();
char charac;
cout << "Enter your letter : " << endl;
cin>>charac;
cout << "The 2 letters are : " << endl;
cout << (char)(charac-1) << endl;
cout << (char)(charac+1) << endl;
getch();
}
This program takes in a letter charac of the English alphabet as a screen input from the user.
It then determines its previous letter and next letter and prints it out using the 'cout' command.

Program to identify if an input is a symbol, digit or character.


#include <iostream.h>
#include <conio.h>

void main()
{
clrscr();
char charac;
cout << "Enter your input : " << endl;
cin>>charac;
if(((charac>='A')&&(charac<='Z'))||((charac>='a')&&(charac<='z')))
cout << "Your input " << charac << " is a character." << endl;
else if((charac>='0')&&(charac<='9'))
cout << "Your input " << charac << " is a digit." << endl;
else
cout << "Your input " << charac << " is a symbol." << endl;
getch();
}
This program takes in a character, a digit or a symbol charac as a screen input from the user.
It then identifies whether the input is a symbol, a digit or a character and outputs the appropriate message using the 'cout' command.

Program to compute the fibonacci series.


#include <iostream.h>
#include <conio.h>

void main()
{
clrscr();
int a,b,x,y,num1,ct;
a=0;
b=1;
cout << "Enter the number of terms (less than 25) : " << endl;
cin>>num1;
cout << a << endl;
cout << b << endl;
for(ct=1;ct<=num1-2;ct++)
{
x=a+b;
cout << x << endl;
y=a;
a=b;
b=x;
}
getch();
}
This program takes in the number of terms num1 in the fibonacci series (less than 25) as a screen input from the user.
It then computes the fibonacci series and prints it out using the 'cout' command.

Program to find the total days in the year till date.


#include <iostream.h>
#include <conio.h>

void main()
{
clrscr();
int day,month,total;
int days_per_month[12]={31,28,31,30,31,30,31,31,30,31,30,31};
cout << "Enter the month : " << endl;
cin>>month;
cout << "Enter the day : " << endl;
cin>>day;
total=day;
for(int x=0;x<month-1;x++)
total+=days_per_month[x];
cout << "The number of days in this year till date = " << total << endl;
getch();
}
This program takes in the current day and month as a screen input from the user.
It then calculates the total number of days in the current year till date and outputs it using the 'cout' command.

Program to convert days into years and weeks.


#include <iostream.h>
#include <conio.h>

void main()
{
clrscr();
int days,years,weeks,num1;
cout << "Enter the number of days : " << endl;
cin>>days;
years=days/365;
num1=days-(years*365);
weeks=days/7;
num1=days-(weeks*7);
cout << days << " days = " << endl;
cout << weeks << " weeks OR " << endl;
cout << years << " years." << endl;
getch();
}
This program takes in the number of days days as a screen input from the user.
It then converts the days into years as well as weeks and outputs it using the 'cout' command.

Program to convert 2-digit octal number into binary number and print it


#include <iostream.h>
#include <conio.h>
void octobin(int);

void main()
{
clrscr();
int a;
cout << "Enter a 2-digit octal number : ";
cin>>a;
octobin(a);
getch();
}
void octobin(int oct)
{
long bnum=0;
int A[6];
//Each octal digit is converted into 3 bits, 2 octal digits = 6 bits.
int a1,a2,quo,rem;
a2=oct/10;
a1=oct-a2*10;
for(int x=0;x<6;x++)
{
A[x]=0;
}
//Storing the remainders of the one's octal digit in the array.
for (x=0;x<3;x++)
{
quo=a1/2;
rem=a1%2;
A[x]=rem;
a1=quo;
}
//Storing the remainders of the ten's octal digit in the array.
for(x=3;x<6;x++)
{
quo=a2/2;
rem=a2%2;
A[x]=rem;
a2=quo;
}
//Obtaining the binary number from the remainders.
for(x=x-1;x>=0;x--)
{
bnum*=10;
bnum+=A[x];
}
cout << "The binary number for the octal number " << oct << " is " << bnum << "." << endl;
}
This program takes in a two-digit octal number a as a screen input from the user.
It then converts the octal number into a binary number and outputs it using the 'cout' command.